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Answer by dlask for pythonic way to get index,column for value == 1
>>> import numpy>>> a = numpy.array([[1, 0, 1], [0, 1, 1], [0, 1, 0]])>>> numpy.transpose(numpy.nonzero(a))array([[0, 0], [0, 2], [1, 1], [1, 2], [2, 1]])
View Articlepythonic way to get index,column for value == 1
I currently have a MxN dataframe which contains a solution to an optimization problem. "Active" i,j for i in {M} and j in {N} pairs are represented by 1 and "inactive" pairs by 0. I need to determine...
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